TCS NQT 2020 Coding Questions With Answers | TCS NQT Programming Logic Questions

A. Places the program in the memory for the purpose of execution.
B. Relocates the program to execute from the specific memory area allocated to it.
C. Links the program with other programs needed for its execution.
D. Interfaces the program with the entities generating its input data.

The correct answer is A linker program “links the program with other programs needed for its execution.”

A. Allocation
B. Translation
C. Relocation
D. Loading

The correct answer is “translation” is not a function of a loader.

The result of the expression 4^12 is:

A. 2
B. 4
C. 8
D. 12

The result of the expression 4^12 computes to 8. ^ is the XOR operator. The binary form of 4 is 0100 and that of 12 is 1100. Therefore, 0010 ^ 1100 evaluates to 1000, which is equal to 8 in decimal format.

A. 01011000
B. 00111000
C. 10001000
D. 00010100

The binary coding for the letter X is 01011000. Here, 0101 is the zone whereas 1000 is the digit. The alphabets from P to Z have the zone 0101.

A. D E B F G C A
B. E D B G F C A
C. E D B F G C A
D. D E F G B C A

Below is the given tree.

           A
                         /     \
                       /        \
                     B           C
                    /   \        /  \
                  /      \     /    \
                 D      E   F       G

# include<stdio.h>
# include<conio.h>
void main()
{
    float a = 100.00;
   {
      auto float a = 250.14;
    {
           auto float b = 325;
          printf(“\n%f %f”, a, b);
          b++;
     }
     a++;
     printf(“\n%f %f”, a, b);
     a++;
  }
 printf(“\n%f”, a);
 }

A. line number 5
B. line number 7
C. line number 9
D. line number 14

The variable ‘b’ is declared in the inner block and is accessed in the outer block. Declare ‘b’ globally to remove the error.

#include <stdio.h>
int main()
{
  int i = 3;
  switch (i)
  {
    case 0+1: printf(“Cyber”);
           break;
    case 1+2: printf(“Tecz”);
            break;
    default: printf(“CyberTecz”);
   }
 return 0;
}

A. Cyber
B. Tecz
C. CyberTecz
D. Compiler error

Expression gets evaluated in cases. The control goes to the second case block after evaluating 1+2 = 3 and “Online” is printed.

A. Return
B. Static
C. New
D. Volatile

“return” keyword gives a value obtained in a function to the main.